Optimal. Leaf size=668 \[ \frac{3746304 \sqrt{2} 3^{3/4} a^{16/3} \left (\sqrt [3]{a}-\sqrt [3]{a-b x^2}\right ) \sqrt{\frac{a^{2/3}+\sqrt [3]{a} \sqrt [3]{a-b x^2}+\left (a-b x^2\right )^{2/3}}{\left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )^2}} F\left (\sin ^{-1}\left (\frac{\left (1+\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}}{\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}}\right )|-7+4 \sqrt{3}\right )}{267995 b x \sqrt{-\frac{\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )}{\left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )^2}}}-\frac{5619456 \sqrt [4]{3} \sqrt{2+\sqrt{3}} a^{16/3} \left (\sqrt [3]{a}-\sqrt [3]{a-b x^2}\right ) \sqrt{\frac{a^{2/3}+\sqrt [3]{a} \sqrt [3]{a-b x^2}+\left (a-b x^2\right )^{2/3}}{\left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )^2}} E\left (\sin ^{-1}\left (\frac{\left (1+\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}}{\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}}\right )|-7+4 \sqrt{3}\right )}{267995 b x \sqrt{-\frac{\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )}{\left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )^2}}}-\frac{11238912 a^5 x}{267995 \left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )}+\frac{2809728 a^4 x \left (a-b x^2\right )^{2/3}}{267995}+\frac{1404864 a^3 x \left (a-b x^2\right )^{5/3}}{191425}-\frac{33264 a^2 x \left (a-b x^2\right )^{8/3}}{14725}-\frac{432}{775} a x \left (a-b x^2\right )^{8/3} \left (3 a+b x^2\right )-\frac{3}{31} x \left (a-b x^2\right )^{8/3} \left (3 a+b x^2\right )^2 \]
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Rubi [A] time = 1.29296, antiderivative size = 668, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333 \[ \frac{3746304 \sqrt{2} 3^{3/4} a^{16/3} \left (\sqrt [3]{a}-\sqrt [3]{a-b x^2}\right ) \sqrt{\frac{a^{2/3}+\sqrt [3]{a} \sqrt [3]{a-b x^2}+\left (a-b x^2\right )^{2/3}}{\left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )^2}} F\left (\sin ^{-1}\left (\frac{\left (1+\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}}{\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}}\right )|-7+4 \sqrt{3}\right )}{267995 b x \sqrt{-\frac{\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )}{\left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )^2}}}-\frac{5619456 \sqrt [4]{3} \sqrt{2+\sqrt{3}} a^{16/3} \left (\sqrt [3]{a}-\sqrt [3]{a-b x^2}\right ) \sqrt{\frac{a^{2/3}+\sqrt [3]{a} \sqrt [3]{a-b x^2}+\left (a-b x^2\right )^{2/3}}{\left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )^2}} E\left (\sin ^{-1}\left (\frac{\left (1+\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}}{\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}}\right )|-7+4 \sqrt{3}\right )}{267995 b x \sqrt{-\frac{\sqrt [3]{a} \left (\sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )}{\left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )^2}}}-\frac{11238912 a^5 x}{267995 \left (\left (1-\sqrt{3}\right ) \sqrt [3]{a}-\sqrt [3]{a-b x^2}\right )}+\frac{2809728 a^4 x \left (a-b x^2\right )^{2/3}}{267995}+\frac{1404864 a^3 x \left (a-b x^2\right )^{5/3}}{191425}-\frac{33264 a^2 x \left (a-b x^2\right )^{8/3}}{14725}-\frac{432}{775} a x \left (a-b x^2\right )^{8/3} \left (3 a+b x^2\right )-\frac{3}{31} x \left (a-b x^2\right )^{8/3} \left (3 a+b x^2\right )^2 \]
Antiderivative was successfully verified.
[In] Int[(a - b*x^2)^(5/3)*(3*a + b*x^2)^3,x]
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Rubi in Sympy [A] time = 102.624, size = 544, normalized size = 0.81 \[ - \frac{5619456 \sqrt [4]{3} a^{\frac{16}{3}} \sqrt{\frac{a^{\frac{2}{3}} + \sqrt [3]{a} \sqrt [3]{a - b x^{2}} + \left (a - b x^{2}\right )^{\frac{2}{3}}}{\left (\sqrt [3]{a} \left (-1 + \sqrt{3}\right ) + \sqrt [3]{a - b x^{2}}\right )^{2}}} \sqrt{\sqrt{3} + 2} \left (\sqrt [3]{a} - \sqrt [3]{a - b x^{2}}\right ) E\left (\operatorname{asin}{\left (\frac{\sqrt [3]{a} \left (1 + \sqrt{3}\right ) - \sqrt [3]{a - b x^{2}}}{- \sqrt [3]{a} \left (-1 + \sqrt{3}\right ) - \sqrt [3]{a - b x^{2}}} \right )}\middle | -7 + 4 \sqrt{3}\right )}{267995 b x \sqrt{- \frac{\sqrt [3]{a} \left (\sqrt [3]{a} - \sqrt [3]{a - b x^{2}}\right )}{\left (\sqrt [3]{a} \left (-1 + \sqrt{3}\right ) + \sqrt [3]{a - b x^{2}}\right )^{2}}}} + \frac{3746304 \sqrt{2} \cdot 3^{\frac{3}{4}} a^{\frac{16}{3}} \sqrt{\frac{a^{\frac{2}{3}} + \sqrt [3]{a} \sqrt [3]{a - b x^{2}} + \left (a - b x^{2}\right )^{\frac{2}{3}}}{\left (\sqrt [3]{a} \left (-1 + \sqrt{3}\right ) + \sqrt [3]{a - b x^{2}}\right )^{2}}} \left (\sqrt [3]{a} - \sqrt [3]{a - b x^{2}}\right ) F\left (\operatorname{asin}{\left (\frac{\sqrt [3]{a} \left (1 + \sqrt{3}\right ) - \sqrt [3]{a - b x^{2}}}{- \sqrt [3]{a} \left (-1 + \sqrt{3}\right ) - \sqrt [3]{a - b x^{2}}} \right )}\middle | -7 + 4 \sqrt{3}\right )}{267995 b x \sqrt{- \frac{\sqrt [3]{a} \left (\sqrt [3]{a} - \sqrt [3]{a - b x^{2}}\right )}{\left (\sqrt [3]{a} \left (-1 + \sqrt{3}\right ) + \sqrt [3]{a - b x^{2}}\right )^{2}}}} + \frac{11238912 a^{5} x}{267995 \left (\sqrt [3]{a} \left (-1 + \sqrt{3}\right ) + \sqrt [3]{a - b x^{2}}\right )} + \frac{2809728 a^{4} x \left (a - b x^{2}\right )^{\frac{2}{3}}}{267995} + \frac{1404864 a^{3} x \left (a - b x^{2}\right )^{\frac{5}{3}}}{191425} - \frac{33264 a^{2} x \left (a - b x^{2}\right )^{\frac{8}{3}}}{14725} - \frac{432 a x \left (a - b x^{2}\right )^{\frac{8}{3}} \left (3 a + b x^{2}\right )}{775} - \frac{3 x \left (a - b x^{2}\right )^{\frac{8}{3}} \left (3 a + b x^{2}\right )^{2}}{31} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((-b*x**2+a)**(5/3)*(b*x**2+3*a)**3,x)
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Mathematica [C] time = 0.0849968, size = 110, normalized size = 0.16 \[ \frac{3 \left (6243840 a^5 x \sqrt [3]{1-\frac{b x^2}{a}} \, _2F_1\left (\frac{1}{3},\frac{1}{2};\frac{3}{2};\frac{b x^2}{a}\right )+5815935 a^5 x-5312355 a^4 b x^3-1675114 a^3 b^2 x^5+749658 a^2 b^3 x^7+378651 a b^4 x^9+43225 b^5 x^{11}\right )}{1339975 \sqrt [3]{a-b x^2}} \]
Antiderivative was successfully verified.
[In] Integrate[(a - b*x^2)^(5/3)*(3*a + b*x^2)^3,x]
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Maple [F] time = 0.045, size = 0, normalized size = 0. \[ \int \left ( -b{x}^{2}+a \right ) ^{{\frac{5}{3}}} \left ( b{x}^{2}+3\,a \right ) ^{3}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((-b*x^2+a)^(5/3)*(b*x^2+3*a)^3,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (b x^{2} + 3 \, a\right )}^{3}{\left (-b x^{2} + a\right )}^{\frac{5}{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + 3*a)^3*(-b*x^2 + a)^(5/3),x, algorithm="maxima")
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (-{\left (b^{4} x^{8} + 8 \, a b^{3} x^{6} + 18 \, a^{2} b^{2} x^{4} - 27 \, a^{4}\right )}{\left (-b x^{2} + a\right )}^{\frac{2}{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + 3*a)^3*(-b*x^2 + a)^(5/3),x, algorithm="fricas")
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Sympy [A] time = 21.0275, size = 139, normalized size = 0.21 \[ 27 a^{\frac{14}{3}} x{{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{1}{2} \\ \frac{3}{2} \end{matrix}\middle |{\frac{b x^{2} e^{2 i \pi }}{a}} \right )} - \frac{18 a^{\frac{8}{3}} b^{2} x^{5}{{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{5}{2} \\ \frac{7}{2} \end{matrix}\middle |{\frac{b x^{2} e^{2 i \pi }}{a}} \right )}}{5} - \frac{8 a^{\frac{5}{3}} b^{3} x^{7}{{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{7}{2} \\ \frac{9}{2} \end{matrix}\middle |{\frac{b x^{2} e^{2 i \pi }}{a}} \right )}}{7} - \frac{a^{\frac{2}{3}} b^{4} x^{9}{{}_{2}F_{1}\left (\begin{matrix} - \frac{2}{3}, \frac{9}{2} \\ \frac{11}{2} \end{matrix}\middle |{\frac{b x^{2} e^{2 i \pi }}{a}} \right )}}{9} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-b*x**2+a)**(5/3)*(b*x**2+3*a)**3,x)
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int{\left (b x^{2} + 3 \, a\right )}^{3}{\left (-b x^{2} + a\right )}^{\frac{5}{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b*x^2 + 3*a)^3*(-b*x^2 + a)^(5/3),x, algorithm="giac")
[Out]